]> Bridge Constructor in Concrete

Bridge Constructor in Concrete

The site is converted from Bridge Constructor under the assumption that 2.5 meters (the width of a square on the default grid) is equivalent to 8 feet. (In reality, 2.5 m ≈ 8.202 ft.)

The bridge is composed entirely of plain (unreinforced) class A concrete, with density (ρ) 145 lb/ft3, compressive strength (fc′) 4 klb/in2, tensile strength 0 klb/ft2, shear strength 2(fc′ ⋅ 1 lb/in2)1/2, and modulus of elasticity (E) 1820(fc′ ⋅ 1 klb/in2)1/2. The cross section of the bridge has width (b) 12 ft.

If a member of the bridge is directly beneath the riding surface of the bridge, then the member is a filled member. A filled member is separated into a fill part and a load&h;bearing part. The fill part&a;s upper profile and lower profile are defined by two separate functions. The load&h;bearing part&a;s upper profile is identical to the fill part&a;s lower profile, but the load&h;bearing part is designed as if its centerline profile were identical to the fill part&a;s lower profile. The load&h;bearing part has a rectangular cross section with height h. It is assumed that axial load and flexural load are resisted by only the load&h;bearing part, while shear load is resisted by both parts.

If a member of the bridge is not a filled member, then it is an unfilled member. An unfilled member has a rectangular cross section with height h, and its centerline profile is defined by a function. It has buckling strength of π2EI ÷ ℓ2, where I (the cross section&a;s second moment of area) is min(b, h)3max(b, h) ÷ 12 and ℓ is the length of the member.

The live load on the riding surface of the bridge consists of: cars, represented with a uniform load of 640 lb/ft; and a truck, represented with a point load of 72 klb.

Camatuga

Island 1

(Westlands)

Site 3

The road passes: from a point at (0 ft, 0 ft); over points at (48 ft, −24 ft) and (112 ft, −24 ft); to a point at (160 ft, 0 ft).

ABC, CDE, and EFG are three&h;hinge arches.

Rotational equilibrium of ABC about A

FB, x, BC(yC − yA) + FB, y, BC(xC − xA) = ρb(∫xAxB((hABℓABxB − xA + yA − (yA + yB − yAxB − xA(x − xA)))(x − xA)dx) + ∫xBxC((hBCℓBCxC − xB + yA − (yB + yC − yBxC − xB(x − xB)))(x − xA)dx)) + σcars∫xAxC((x − xA)dx) + Ftruck(xtruck − xA)(xtruck ∈ (xA, xC))

FB, x, BC(yC − yA) + FB, y, BC(xC − xA) = ρb(∫0 ftxB − xA((hABℓABxB − xA + yA − (yA + yB − yAxB − xAx))xdx) + ∫xB − xAxC − xA((hBCℓBCxC − xB + yA − (yB + yC − yBxC − xB(x − xB + xA)))xdx)) + σcars∫0 ftxC − xA(xdx) + Ftruck(xtruck − xA)(xtruck ∈ (xA, xC))

FB, x, BC(yC − yA) + FB, y, BC(xC − xA) = ρb(∫0 ftxB − xA((hABℓABxB − xA − yB − yAxB − xAx)xdx) + ∫xB − xAxC − xA((hBCℓBCxC − xB − (yB − yA) − yC − yBxC − xB(x − (xB − xA)))xdx)) + σcars∫0 ftxC − xA(xdx) + Ftruck(xtruck − xA)(xtruck ∈ (xA, xC))

FB, x, BC(yC − yA) + FB, y, BC(xC − xA) = ρb(∫0 ftxB − xA((hABℓABxB − xA − yB − yAxB − xAx)xdx) + ∫xB − xAxC − xA((hBCℓBCxC − xB − (yB − yA) − yC − yBxC − xBx + (yC − yB)(xB − xA)xC − xB)xdx)) + σcars∫0 ftxC − xA(xdx) + Ftruck(xtruck − xA)(xtruck ∈ (xA, xC))

FB, x, BC(yC − yA) + FB, y, BC(xC − xA) = ρb(∫0 ftxB − xA((hABℓABxB − xA − yB − yAxB − xAx)xdx) + ∫xB − xAxC − xA((hBCℓBC − (yC − yB)(xB − xA)xC − xB − (yB − yA) − yC − yBxC − xBx)xdx)) + σcars∫0 ftxC − xA(xdx) + Ftruck(xtruck − xA)(xtruck ∈ (xA, xC))

FB, x, BC(yC − yA) + FB, y, BC(xC − xA) = ρb((hABℓAB2(xB − xA)x2 − yB − yA3(xB − xA)x3)0 ftxB − xA + (hBCℓBC − (yC − yB)(xB − xA) − (yB − yA)(xC − xB)2(xC − xB)x2 − yC − yB3(xC − xB)x3)xB − xAxC − xA) + σcars(12x2)0 ftxC − xA + Ftruck(xtruck − xA)(xtruck ∈ (xA, xC))

FB, x, BC(yC − yA) + FB, y, BC(xC − xA) = ρb(hABℓAB(xB − xA)2 − (yB − yA)(xB − xA)23 + hBCℓBC − (yC − yB)(xB − xA) − (yB − yA)(xC − xB)2(xC − xB)((xC − xA)2 − (xB − xA)2) − yC − yB3(xC − xB)((xC − xA)3 − (xB − xA)3)) + σcars2(xC − xA)2 + Ftruck(xtruck − xA)(xtruck ∈ (xA, xC))

FB, x, BC(yC − yA) + FB, y, BC(xC − xA) = ρb(hABℓAB(xB − xA)2 − (yB − yA)(xB − xA)23 + hBCℓBC − (yC − yB)(xB − xA) − (yB − yA)(xC − xB)2(xC − xB)(xC2 − 2xCxA + xA2 − xB2 + 2xBxA − xA2) − yC − yB3(xC − xB)((xC − xA)3 − (xB − xA)3)) + σcars2(xC − xA)2 + Ftruck(xtruck − xA)(xtruck ∈ (xA, xC))

Rotational equilibrium of BC about B

Horizontal equilibrium of BC

Vertical equilibrium of BC